A particle executes SHM of period 8 s and amplitude 5 cm. Find the velocity and acceleration when the particle is 3 cm from the central position andalso their maximum values.

Dear Student,

Equation of position of particle during SHM,x=Asinωt+ϕdifferentiating,v=Aωcosωt+ϕAgain differentiating,a=-Aω2sinωt+ϕGiven,T=8 secA=5cmx=3ω=2πT=π43=5sinωt+ϕsinωt+ϕ=35cosωt+ϕ=±45v=±5×π4×45=π cm/seca=-5×π42×35=-3π216cm/sec2

Regards,

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