A particle moves under the effect of force of F=cx from x=0 to x=x1 The work done in the - Physics - Work Energy And Power

Question

A particle moves under the effect of force of F=cx from
x=0 to x=x 1 The work done in
the process is (i)cx12 (ii) 1/2
cx12 (iii)cx13 (iv)
zero

Bapan Pathak · Accepted Answer

Hi Papu,
The force given here is dependent on the position of the
particle So, we will have to find the work done on the particle for
a small displacement and then integrate it to find the net work
done by the force over the displacement from x = 0 to
x = x1
We have, F = cx
For a small displacement dx the work done on the
particle is,
<img width="442" height="284" src=
"https://s3mn%20mnimgs%20com/img/shared/userimages/mn_images/image/q1(1)%20png"
alt="">

Hope this helps you understand how to solve
problems of this kind
Do write back if you have any doubt or
confusion in any of the steps
Keep posting
& have a great day!

A particle moves under the effect of force of F=cx from x=0 to x=x 1. The work done in the process is (i)cx12 (ii) 1/2 cx12 (iii)cx13 (iv) zero .

A particle moves under the effect of force of F=cx from x=0 to x=x ₁. The work done in the process is (i)cx_1²(ii) 1/2 cx_1² (iii)cx_1³ (iv) zero .