A particle starts from rest with an acceleration a= lambda/x^2, where lambda 0 and x is the distance of - Physics - Motion In A Straight Line

Question

A particle starts from rest with an acceleration a= lambda/x^2,
where lambda >0 and x is the distance of the particle from a
fixed point O The particle is at a distance of u from O, when it is
at rest Its velocity when at a distance 2u from O is

Vijay Shankar Yadav · Accepted Answer

Dear Student,
here given  a=λx2⇒dvdtdxdx=λx2⇒dvdxv=λx2⇒∫0v'vdv=∫u2uλx2dx⇒v'2/2=-λxu2u⇒v'2/2=-λ2u+λu=λ2uv'=λuunit
Regard

A particle starts from rest with an acceleration a= lambda/x^2, where lambda >0 and x is the distance of the particle from a fixed point O. The particle is at a distance of u from O, when it is at rest. Its velocity when at a distance 2u from O is