a particle starts with angular acceleration 2 rad/sec^2 it moves 100 rad in a random interval of 5 sec - Physics - Laws Of Motion

Question

a particle starts with angular acceleration 2 rad/sec^2 it moves
100 rad in a random interval of 5 sec ​Find out the time at
which random interval starts

Sanjay Singh · Accepted Answer

Dear student

Let motion starts at time t=0  and and random counting of time begins at t=T secAngular velocity of the particle at time T isω=ωo+αTω(T)=0+2T
1Angle rotated by the particle in 5 second after this isθ=ω(T)×t+12αt2θ=2T×5+12×2×52100=2T×5+2510T=75T=7
5 secRegards

a particle starts with angular acceleration 2 rad/sec^2. it moves 100 rad in a random interval of 5 sec. ​Find out the time at which random interval starts.

a particle starts with angular acceleration 2 rad/sec^2. it moves 100 rad in a random interval of 5 sec. Find out the time at which random interval starts.