a point mass oscillates along the x-axis according to the law x=xₒcos (wt -π/4).if the acceleration of the particle is written as a = A cos(wt + δ) then A = and δ = ? Share with your friends Share 9 Ujjval Chauhan answered this Dear student Given that x=xocosωt-π4so v=dxdt=-xoωsinωt-π4again differentiatinga=dvdt=-xoω2cosωt-π4a=-xoω2cosωt-π4absorbing the negative sign in cosine term ascosωt-π4+π=-cosωt-π4so -cosωt-π4=cosωt+3π4a=xoω2cosωt+3π4Thus on comparison A=xoω2 and δ=3π4 56 View Full Answer Soutik Nandy answered this Hope you get it -27 Chandni Jain answered this wrong answer -14 Chandni Jain answered this answer is A=xₒw² and δ = 3π/4 -9 Soutik Nandy answered this Chandini if theta is -?/4 then it is 3?/4 only -6 Soutik Nandy answered this And magnitude of A is x 0 omega ^2 -7