a solid AB has zns type structure. the edge length of unit cell is 400pm and the radius of B- ion is 0.130nm. then radius of A+ion is

Dear student
Please find below the solution to the asked query:

ZnS has a fcc structure
For a fcc unit cell:
a = 2r+ + 2r-
where r+ is the radius of the cation
r- is the radius of the anion
a is the edge length
so
r⁺ +r^- = a/2
a =400pm = 400 x 0.001 nm = 0.4 nm
0.130 +r⁺ = 0.4/2
r+ = 0.47 nm

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