A solution containing 13.5g urea per 500ml of solution in water has same osmotic pressure as solution of sucrose in water. Calculate the mass of sucrose present in 500ml of its solution.
We use formula, π =
Where π is osmotic pressure
R is gas constant
T is temperature in Kelvin
V is volume of solution in L
n2 = moles of solute
For both urea and sucrose solution, R, T and V are the same.
So, for osmostic pressure the moles of urea and sucrose present should be the same.
calculating the moles of urea and finding the mass of those moles for sucrose gives the answer.
Moles of urea = 13.5/60 = 0.225mol (molar mass of urea = 60g/mol)
Mass of 0.225mol of sucrose = 0.225 342 = 50.625g (molar mass of sucrose = 342g/mol)
Where π is osmotic pressure
R is gas constant
T is temperature in Kelvin
V is volume of solution in L
n2 = moles of solute
For both urea and sucrose solution, R, T and V are the same.
So, for osmostic pressure the moles of urea and sucrose present should be the same.
calculating the moles of urea and finding the mass of those moles for sucrose gives the answer.
Moles of urea = 13.5/60 = 0.225mol (molar mass of urea = 60g/mol)
Mass of 0.225mol of sucrose = 0.225 342 = 50.625g (molar mass of sucrose = 342g/mol)