A solution containing 2.675g of CoCl3.6NH3 is passed through a cation exchanger .The chloride ions obtained in the solution were treated with excess of AgNO3to give 4.78of AgCl.The formula of the complex ??

Mass of CoCl3.6NH3=2.675 gMolecular mass of CoCl3.6NH3= 267.5 g mol-1Number of moles of CoCl3.6NH3=massmolecular mass=2.675267.50=0.01 molesMass of AgCl obtained = 4.78 gNumber of moles of AgCl = 4.78143.5=0.03 molesSince, 0.01 moles of the complex give 0.03 moles of AgCl on reaction with AgNO3, this indicates that it contains 3 ionisable chlorines.So, the formula of the complex is: [Co(NH3)6 ]Cl3

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