A source on a swing which is covering an angle θ from the vertical is producing a frequency v. The source is distant d from the place of support of swing. If velocity of sound is c, acceleration due to gravity is g, then the maximum and minimum frequency heard by a listener in front of swing is  

(A)  cv 2 gd - c , cv 2 gd + c
(B)  cv 2 gd   1 - cosθ - c , cv 2 gd   1 - cosθ + c
(C)  cv c - 2 gd   1 - cosθ   , cv c + 2 gd   1 - cosθ
(D)  cv c - 2 gd   1 - sinθ   , cv c + 2 gd   1 - sinθ

Dear Student,

In this question we use doppler effect
when the speed of source is maximum towards the observer at that time frequency heard is maximum.when the source speed is maximum away from the observer at thhat time frequency is minimum.for both case the maximum speed is same but have opposite direction .speed at mean position is maximum.mv22=mgd-dsinθv=2gd1-sinθ m/smaximum frequencyfmax=νcc-2gd1-sinθminimum frequency.fmin=νcc+2gd1-sinθhence option d is correct.Regards

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