A table clock has its minute hand 4.0 cm long. Find the average velocity of the tip of the minute hand (a) between 6.00 a.m. to 6.30 a.m. and (b) between 6.00 a.m. to 6.30 p.m.

Dear Student,

Please find below the solution of your asked query:

(i) Displacement = 8 cm, from 4 cm above the centre at 6:00 AM to 4 cm below the centre at 6:30 AM.
                   8 cm = 0.08 m 

Time taken by displacement takes 30 minutes = 1800 seconds. 

Average velocity = displacement / time
Average velocity = 0.08 / 1800
                             = 4.44 × 10-5 m/s


(ii) Displacement = 8 cm, from 4 cm above the centre at 6:00 AM to 4 cm below the centre at 6:30 PM. 
                     8 cm = 0.08 m 

Time taken by displacement 12.5 hours = 45,000 seconds. 

Average velocity = displacement / time
Average velocity = 0.08 / 45000 = 1.777 × 10-6 m/s
                                                     = 1.78 × 10-6 m/s

Hope this information clears your doubts about the topic.

Keep asking!!

Regards

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