A weight is attached to the free end of a sonometer wire. It gives resonance at a length 40 cm when it is resonanced with a tuning fork
of frequency 51 Hz. The weight is then immersed wholly in water, the resonant length is reduced to 30 cm. The relative density in which weight suspended is
(A) 16/9 (B) 16/7 (C) 16/5 (D) 16/3 . Please also tell chapter name@ no links .

Dear Student,
frequencyfλwavelengthfor constant frequency,λ is proportinal to ω12λ1λ2=ω1ω212.......(1)ω1=Df1 and ω2=Df1-Dwf1where,D is the density of material,Dw is the density of water.given,λ1=40 cm ,λ2=30 cm,f1=51 Hz,putting these values in equation(1)4030=Df1Df1-Dwf112=DD-Dw12DD-Dw12=43DD-Dw=169D-DwD=9161-DwD=916DwD=1-916=716DDw=167option(B) is correct.
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