A wire suspended vertically from one of its ends is streched by attaching a weight of 200N to the lower end. The weight streches the wire by 1mm. The elastic energy stored in the wire is :

(A) 0.2 J

(B) 10 J

(C) 20J

(D) 0.1J

Using the simple relation for a stretched wire potential energy , U = (1/2) F ΔL, we can get the answer as follows

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