A wire suspended vertically from one of its ends is streched by attaching a weight of 200N to the lower end. The weight streches the wire by 1mm. The elastic energy stored in the wire is :
(A) 0.2 J
(B) 10 J
(C) 20J
(D) 0.1J
Using the simple relation for a stretched wire potential energy , U = (1/2) F ΔL, we can get the answer as follows