after electrolysis of NaCl solution with inert electrodes for certain time period, 600 ml of solution was left which was found to be 1N in NaOH... during same time, 31.75 g of Copper was deposited in Cu voltmeter in series with electrolytic cell.calculate percentage yield of NaOH obtained?
Dear Student,
Please find below the solution to the asked query:
Equivalent mass of NaOH in 600ml of 1N NaOH = (40 g /1000 ml) x 600 ml = 24 g
Amount of NaOH formed = (40/1000) x 600 = 24 g
31.75 g of Cu = 1 gram equivalent of Cu.
Since, it is connected in series, during the same period, 1 gram equivalent of NaOH should have been formed, which is = 40 g . But the amount of NaOH obtained is only 24 g.
Hence, the % yield = (24/40) x 100 = 60 %
Hope this information will clear your doubts about Electrochemistry.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
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Please find below the solution to the asked query:
Equivalent mass of NaOH in 600ml of 1N NaOH = (40 g /1000 ml) x 600 ml = 24 g
Amount of NaOH formed = (40/1000) x 600 = 24 g
31.75 g of Cu = 1 gram equivalent of Cu.
Since, it is connected in series, during the same period, 1 gram equivalent of NaOH should have been formed, which is = 40 g . But the amount of NaOH obtained is only 24 g.
Hence, the % yield = (24/40) x 100 = 60 %
Hope this information will clear your doubts about Electrochemistry.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
Best Wishes !