An aqueous solution is prepared by diluting 3 30 mL acetone (d = 0 789 g/mL) with water to a - Chemistry - Solutions

Question

An aqueous solution is prepared by diluting 3 30 mL acetone (d = 0
789 g/mL) with water to a final volume of 75 0 mL The density of
solution is 0 993 g/mL What are the molarity and molality of
acetone in this solution?

Chanda Rawat · Accepted Answer

Dear student,

mass of acetone: (3 30 mL) (0 789 g/mL) = 2 6037 g

moles of acetone: 2 6037 g / 58 0794 g/mol = 0 04483 mol

mass of solution: (75 0 mL) (0 993 g/mL) = 74 475 g

mass of water in the solution: 74 475 g - 2 6037 g = 71 8713 g

moles of water: 71 8713 g / 18 015 g/mol =

Molarity:

0 04483 mol / 0 0750 L = 0 598 M

Molality:

0 04483 mol / 0 0718713 kg = 0 624 m

Regards

An aqueous solution is prepared by diluting 3.30 mL acetone (d = 0.789 g/mL) with water to a final volume of 75.0 mL. The density of solution is 0.993 g/mL . What are the molarity and molality of acetone in this solution?