an object is projected from ground with speed u at an angle theta with horizontal. the radius of curvature os its trajectory at maximum height from ground is

Projectile motion
 
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Projectile motion
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Projectile motion
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Let a=g exerted on max. height, v be the velocity at max.height that is u cos theta and R be the radius of curvature.

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U?sin?theta/2g
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Max height=(U?Sin theta)^2+2g
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Hope it will help you 😊😊

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Please find this answer

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u^2 cos theta/g 
 
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