An object is thrown vertically upwards in such a way that it has a speed of 19.6m/s when it reaches one half its maximum altitude what are (a) its maximum altitude (b) its velocity 1 sec after is thrown and (c) its acceleration when it reaches its maximum altitude.

please answer as soon as possible!!

Dear student, 

(a) Let maximum altitude is h.
Consider motion from one half of maximum to maximum altitude.
v2=u2-2gs0=19.62-2×9.8×h2h=39.2 m

(b) Now, consider motion from ground to maximum altitude.
v2=u2-2gs0=u2-2×9.8×hu=2×9.8×39.2u=19.62 m
Velocity after 1 sec,
v=u-gtv=19.62-9.8×1=9.822-1 m/s
(c) Acceleration at maximum altitude = g = 9.8 m/s2  Downwards
Regards.
 

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