Dear Student Angle of Banking with friction tan θ+μ1-μtanθ =v2rgtan 15 =0 270 27+0 41-0 4×0 27 =v2100×106700 892 =v2751 121 =v2v =27 40 Regards

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Dear Student

A n g l e o f B a n k i n g w i t h f r i c t i o n \frac{\tan θ + μ}{1 - μ \tan θ} = (\frac{v^{2}}{r g}) \tan 15 = 0.27 \frac{0.27 + 0.4}{1 - 0.4 \times 0.27} = (\frac{v^{2}}{100 \times 10}) \frac{670}{0.892} = v^{2} 751.121 = v^{2} v = 27.40

Regards