Dear Student,Given,r=390m , v=32 m/sLet θ be the banking angle'tanθ=v2gr=32×329 8×390=0 2679θ=tan0 2679-1=150 option ARegards

Ans this too

D e a r S t u d e n t, G i v e n, r = 390 m, v = 32 m / s L e t θ b e t h e b a n k i n g a n g l e' \tan θ = \frac{v^{2}}{g r} = \frac{32 \times 32}{9.8 \times 390} = 0.2679 θ = \tan {(0.2679)}^{- 1} = 15^{0} . o p t i o n A R e g a r d s . .