Ans Ans 3 5 waæ O' 02 mL " (V) 0 4 aqueous of NH, , Gtve a mmng of 20", 200 q ot anc 400 g of æauea.ß Of NOCI massczj mole NaCi mass NOCI What of (4) SCO ct of SCtÆ,on (3) too ot 200 of . u •dssoe.•ectnH cf na.•og 0 2 the mass Of be Gwen tre molantv moat/ c' so'..'tjcn H SO, s 98". by mass anc nave a censitv Share with your friends Share 0 Vartika Jain answered this Dear Student, 3. 100 g of 20% solution contains solute = 20100×100=20 g 200 g of 30% solution contains solute = 30100×200 = 60 g400 g of 10% solution contains solute =10100×400 = 40 gTotal mass of solute = 20+60+40=120 gTotal mass of solution = 100+200+400=700 gSo, Mass of water=Mass of solution-Mass of solute =700-120 =580 g(a) % by mass of solution =120700×100 = 17.14%(b) Mole fraction of NaCl = Moles of NaClMoles of NaCl + Moles of water =1202312023+58018 =5.215.21+32.22 =5.2137.43 =0.139(3) Molality=Mass of NaClMolar mass of NaCl×1000Mass of solvent =12023×1000580 =8.99 molal(4) Mass fraction =Mass of NaClMass of solution =120700 =0.171Kindly ask the remaining query in the next thread. -1 View Full Answer Ragesh answered this 5(1) 6(1.4) 0
