Answer this maths question

Dear student

Since AB = AC \Rightarrow ∠ ABC = ∠ ACB [Angles opposite to equal sides are equal] . . . (1) Since O is the bisector of ∠ B and ∠ C So, ∠ ABO = ∠ OBC = \frac{1}{2} ∠ ABC . . . (2) and ∠ ACO = ∠ OCB = \frac{1}{2} ∠ ACB . . . (3) From (1), (2) and (3) ∠ ABO = ∠ OBC = ∠ ACO = ∠ OCB . . . (4) By angle sum property of triangle in △ BOC ∠ OBC + ∠ OCB + ∠ BOC = 180 ° \Rightarrow ∠ 2 OCB + ∠ BOC = 180 ° \Rightarrow ∠ BOC = 180 ° - 2 ∠ OCB \Rightarrow ∠ BOC = 180 ° - ∠ ACB . . . (5) [∵ ∠ OCB = \frac{1}{2} ∠ ACB] and ∠ ACD = 180 ° - ∠ ACB [Linear pair] . . . . (6) From (5) and (6) ∠ BOC = ∠ ACD

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