at 298 K and 1 atm pressure , solubility of N2 in water was found to be 6 8*10-4 mol/L - Chemistry - Solutions

Question

at 298 K and 1 atm pressure , solubility of N2
in water was found to be 6 8*10-4 mol/L if the partial
pressure of N2 is 0 78 atm then what is the
concentration of N2 dissolved in water under atmospheric
conditions

Tinku Jangra · Accepted Answer

Henry's Law : p=KHCp=partial pressureKH=Henry's ConstantC = ConcentrationSo, Solubility of N2 at 1atm = 6
8×10-4mol/Lp=1 atmSo, KH=pC=16 8×10-4=1
47×103 atm/molWhen the partial pressure = 0
78 atmC = pKH=0 781 47×103=0 53×10-3=5
3×10-4 mol/L

at 298 K and 1 atm pressure , solubility of N2 in water was found to be 6.8*10-4 mol/L . if the partial pressure of N2 is 0.78 atm . then what is the concentration of N2 dissolved in water under atmospheric conditions

at 298 K and 1 atm pressure , solubility of N₂ in water was found to be 6.8*10^-4 mol/L . if the partial pressure of N₂ is 0.78 atm . then what is the concentration of N₂ dissolved in water under atmospheric conditions