At STP speed of sound is 332 m/s on a perticular day a sound propogates through the atmostphere at 340 m/s assume constant ATM then what is the ATM on the perticular day 

Dear Student,

by the following formula,

vsound=vSTP+0.6Tcurrentlyor T=vsound-vSTP0.6=13.33 °C

Regards.

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