At STP speed of sound is 332 m/s on a perticular day a sound propogates through the atmostphere at 340 m/s assume constant ATM then what is the ATM on the perticular day Share with your friends Share 0 Sayantan answered this Dear Student, by the following formula, vsound=vSTP+0.6Tcurrentlyor T=vsound-vSTP0.6=13.33 °C Regards. 0 View Full Answer Apoorv Tyagi answered this Your question seems incorrect.Please elaborate it. -1