board question . Share with your friends Share 1 Aditi answered this a) Given :at t= 0 , x= 0uy=10 m/s , ux=0ax=8 m/s2 , ay=2 m/s2x= uxt+12×ax×t216=12×8 ×t2t2=4t = 2 secy = uyt+12×ay×t2y=10 ×2+12×2×22y =20+ 4 = 24 m(b)vx=ux+ax×tvx=0+8×2vx=16 i⏜vy=uy+ay×t = 10+2×2 = 10 + 4 = 14 j^v=16 i⏜+ 14 j^So , speed =256+196=21.26 m/s 1 View Full Answer