Calculate moment of inertia of a uniform circular ring of mass 1-5 kg and diameter 50 cm about a diameter of the ring......

Hi Olivea,

Here, M = 1.5 kg, R = 50/2 = 25 cm = 1/4 m

About a diameter of the ring, moment of inertia = 1/2 MR²

I = 1/2 x 1.5 x (1/4)² = 0.047 kg m²

Hopes dis will help u :))