calculate the equivalent conductance of 1 M h2so4 solution if its conductivity is 2.6x10 to the power -2 /ohm cm

We know,
Normality = molarity x number of H+ or OH- ions
Normality of 1M H2SO4 = 1 x 2 = 2N

‚ÄčAnd
equivalent conductance, Λeq = conducticity(K) x 1000Normality                                                     =2.6 x 10-2 ohm-1cm-1 x 10002 eq/cm3                                                     =13 ohm-1 cm2 eq-1
 

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