Calculate the Normality of mixture when 200mLof 0.2N HCland 100mLof 0.5 NaOH are mixed they react each other in the reaction HCl+NaOH----> NaCl +H2O

Dear ‚Äč Adithya,

N1V1(acid) - N2V2(base)=Nsolution(V1+V2)(0.2×200)-(0.5×100)=Nsolution×300-10300=Nsolution-ve value indicates that the solution is basic in nature because miliequivalents(meq) of base are greater than the meq of acidSo the normality of solution is 0.033 N.
Regards

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