calculate the osmotic pressure of 0.05%urea solution in water at 20°c.
given:- R=0.0821Latm per mole per Kelvin;Molar mass of urea = 20g per mole
o.p=CRT
no of moles of urea=0.05/60 (molecular weight of urea=60)
=8 x 10-4
C=8 x 10-4/20 x 10-3 ; T=273+20=293K
osmotic pressure = 0.04 x 0.0821 x 293
=0.962 atm
no of moles of urea=0.05/60 (molecular weight of urea=60)
=8 x 10-4
C=8 x 10-4/20 x 10-3 ; T=273+20=293K
osmotic pressure = 0.04 x 0.0821 x 293
=0.962 atm