Calculate the potential of the half cell containing 0.10M K2Cr2O7, 0.20M Cr+2, and 1.0* 10-4M H+. The half cell reaction is

Cr2O7 -2 +14 H++ 6e---------------- 2Cr+3 +7 H20

The standard electrode potential is given as 1.33V.???

 Cr2O7 -2 +14 H++ 6e---------------- 2Cr+3 +7 H20

Ecell=EĀ°cell-(0.0591/6) log{ [Cr+3]2/ [H+]14 [Cr2O7-2]}

=1.33-(0.0591/6)log{[0.20]2/[(1x10-4)14(0.10)]}

=1.33- 0.54

0.79 V

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