Calculate the pressure inside an air bubble of radius 2cm when it is formed (i) in air (ii) under water 10km below. Surface tension of water is 0.0725N/m. Patm = 1.01325 x 105 N/m2 ..
Pls don t add a hyperlink, but solve , thank u

Dear Student,

barometric pressure, P0=101292.8 N/m2=1.01325×105 N/m2surface tension, σ=0.0725 N/mradius, r=0.2×10-3 mheight, h=10000 mdensity, ρ=13600 kg/m3g=9.8 m/s2In airTotal pressure, P=P0+2σrP=1.01325×105+2×0.07250.2×10-3P=1.01325×105+0.007×105P=1.02025×105 N/m2Under waterTotal pressure, P=P0+2σr+ρghP=1.01325×105+2×0.07250.2×10-3+13600×9.8×10000 P=1.01325×105+0.007×105+13328×105P=13,329.020×105 N/m2
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