Calculate the volume of gas liberated at anode at STP during the electrolysis of CuSO4 solution by passing current of - Chemistry - Electrochemistry

Question

Calculate the volume of gas liberated at anode at STP during the
electrolysis of CuSO4 solution by passing current of 1 A
for 16 minute and 5 second

56 ml
224 ml
112 ml
448 ml

Vartika Jain · Accepted Answer

Dear Student,

Anode : H2O → 2H+ + 12O2 +2e-Cathode : Cu2+ + 2e- → CuQuantity of electricity passed, Q=Itor, Q=1×(16×60+5) = 1×965= 965 CAmount of electrons passed= 96596500=0
01 molOn passing 2 mol of e- ,12 mol of gas is evolved
So, on passing 0
01 mol of electrons, amount of gas evolved = 12×2×0
01=0
0025 mol Volume of O2 liberated = 0
0025×22 4=0
056 L=56 mlHence, the correct answer is (1)

Calculate the volume of gas liberated at anode at STP during the electrolysis of CuSO4 solution by passing current of 1 A for 16 minute and 5 second 56 ml 224 ml 112 ml 448 ml

Calculate the volume of gas liberated at anode at STP during the electrolysis of CuSO₄ solution by passing current of 1 A for 16 minute and 5 second

56 ml

224 ml

112 ml

448 ml