Can someone explain how v got t i am not getting it.. Can someone explain how v got t i am not getting it.. A body is thrown into a river from a steep bank with height H. The initial velocity of the body form an angle with the and its "locity is u. At what distance from the bank will body fall. ) What is the velocity Of the body When it falls into water. Consider path A B with origin at point and X and Y axes as shown. x FIGURE Axis u cos Y- Axis u stn a 2.25 which i expressn No. of unknown variables are fear, vx , vy. R Eqns. along X-axb, 1/2 ai2 R u cos Eqns. along Y-axis, v u + v —u sin a + g/ H — wsin 1/2 02 eqn. we get. gp — (2 sin a) — 2 O 2" sina* 4u2sin2u+8gH (We retain only Sign) Share with your friends Share 0 Vijay Shankar Yadav answered this Dear Student, For finding t here took vertical velocity and height H and applyied second equation of motion we getH=-usin(α)t+12gt2velocity took (-) because its direction different than height and accelarationaftere arranging above equation we get gt2-(2usin(α))t-2H=0use sreedharacharya formula we gett=2usin(α)+4u2sin2(α)+8gH2g Regard 0 View Full Answer
