ch3br, chbr3, ch3cl, ch2cl2.... arrange these in increasing order of boiling point
Dear Student,
Greater the size and mass of the halogen atom, greater will be the magnitude of van der waal forces of attractions and thus greater will be the boiling point. Since increasing order of size and mass of halogen atom is Cl<Br
Therefore, the order will be:
CH3Cl < CH2Cl2 < CH3Br < CHBr3
Greater the size and mass of the halogen atom, greater will be the magnitude of van der waal forces of attractions and thus greater will be the boiling point. Since increasing order of size and mass of halogen atom is Cl<Br
Therefore, the order will be:
CH3Cl < CH2Cl2 < CH3Br < CHBr3