check the dimensional accuracy of the relation T=2pie root l/g?

The given equation is

T = 2π√(l/g)

here

[l] = [M0L1T0]

[g]  = [M0L1T-2]

and

[t] = [M0L0T1]

 

now,on the right hand side

[ [M0L1T0]/[M0L1T-2] ]1/2 = [1/T-2]1/2

or

=  [M0L0T1]

 

which is equal to the LHS. Thus the equation is dimensionally consistent.

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