CONDUCTIVITY OF 0.12M CUSO4 SOLUTION AT 298K IS 1.8*10 RAISE TO -2 S CM . CALCULATE ITS EQUIVALENT CONDUCTIVITY.

Given : Conductivity ($\kappa$) = $1.8\times {10}^{-2} {\mathrm{Scm}}^{-1}$
            Molarity = 0.12 M
​To find out the equivalence conductivity we need to find out the normality of the solution
For  CuSO₄
Cu²⁺ (aq) + 2e^-$\to$ Cu(s)
thus e^- change (n) = 2
Normality = Molarity ​$\times$ n
​                = 0.12  $\times$ 2
                = 0.24 N


Equivalent Conductivity${\wedge }_{eq}$= $\kappa$ $\times \frac{1000}{Normality}$
                                        = $1.8\times {10}^{-2} {\mathrm{Scm}}^{-1}$ $\times \frac{1000 c{m}^3{L}^{-1}}{0.24 g eq L^{-1}}$
                                        = 7500 Scm²​g^-1eq^-1