Consider an elliptically shaped rail PQ in the vertical plane with OP = 3 m and OQ = 4 m. A block of mass 1 kg is pulled along the rail from P to Q with a force of 18 N, which is always parallel to lien PQ (see the figure given). Assuming no frictional losses, the kinetic energy of the block when it reaches Q is (n × 10) Joules. The value of n is (take acceleration due to gravity = 10 ms–2)

Dear student,
Using Work Energy theorem,we know 
Work done=Change in poptential energy+change in kinetic energyF×r=P.Ef-P.Ei+K.Ef-K.Ei18×5=mgh-0+K.Ef-018×5=1×10×4+K.EfK.Ef=90-40K.Ef=50JAs K.Ef=(n×10)Jn=5

Regards.

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