Derive mirror formula for concave mirror forming real image. Share with your friends Share 1 Sanjay Singh answered this Dear studentTriangle ABC is similar to triangle CDEABDE=ACCD....1Triangle DEF is similar to triangle FPSDFDE=FPPS (AB=PS)DFDE=FPABABDE=FPDF....2from 1 and 2ACCD=FPDFAP-CPCP-CD=FPDP-PF(-u)-(-2f)-2f-(-v)=-f-v-(-f)2f-uv-2f=-ff-vcross multiplying andsolving-fu+uv+2f2-2fv=-fv+2f2uv-fu=fvDividing both sides with uvf1u+1v=1fRegards 3 View Full Answer Vinay answered this I don't know ask to your teacher 3
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