domain and range of function f(x)=root(x-1) Share with your friends Share 0 Priyanka Kedia answered this Given, fx=x-1For domain fx should be exists and function fx exists if x-1≥0⇒x≥1Thus, Domain fx∈[1,∞)And,Let y=fx=x-1⇒y2=x-1Since y is in quadratic. Therefore, y≥0Thus, Range fx∈[0,∞) 10 View Full Answer