Expand (x + 2/x)^5 using binomial theorem?

{(x + \frac{2}{x})}^{5} = x^{5} + {}^{5}C_{1} x^{4} {(\frac{2}{x})}^{1} + {}^{5}C_{2} x^{3} {(\frac{2}{x})}^{2} + {}^{5}C_{3} x^{2} {(\frac{2}{x})}^{3} + {}^{5}C_{4} x^{1} {(\frac{2}{x})}^{4} + {(\frac{2}{x})}^{5} = x^{5} + \frac{5!}{1! 4!} x^{4} (\frac{2}{x}) + \frac{5!}{2! 3!} x^{3} (\frac{4}{x^{2}}) + \frac{5!}{2! 3!} x^{2} (\frac{8}{x^{3}}) + \frac{5!}{4! 1!} x^{1} (\frac{16}{x^{4}}) + \frac{32}{x^{5}} = x^{5} + 10 x^{3} + 40 x + \frac{80}{x} + \frac{80}{x^{3}} + \frac{32}{x^{5}}

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