Explain Four point masses each of value m are placed at the corners of a square ABCD of side l. The moment of inertia of this system about an axis passing through A and parallel to BD is : a) 2ml2 b) 3 ml2 c) 3ml2 d) ml2 Share with your friends Share 4 Ujjval Chauhan answered this Dear student The moment of inertia is given by I=mr2, where m is the mass of particle and r is the perpendicular distance of mass from axis of rotation.I=∑14miri2I=m∑14ri2I=mrA2+rB2+rc2+rD2I=m02+l22+l22+l22I=ml22+2l2+l22I=3ml2 20 View Full Answer Akash Dash answered this You want explanation of the question or explanation of the solution to the question? -2 Vijay answered this I want method to solve this question -5
