Find A vector. B vector if modA vector=2 and modB vector =5 and mod of cross product of vector A and vector B=8
|A| = 2 units.
|B| = 5 units.
|A x B| = 8 units.
Now, |A x B| = |A||B|sinθ
8 = 2*5*sinθ
=>sinθ = 8/10
=> θ = sin^-1 (4/5)
=> θ = 53 deg
Now |A|.|B| = |A||B|cosθ
=> 2*5*cos(53)
=> 10*(3/5) => 6