f(x)= 1/1-x^{2},

Denominator should not be equal to 0 as 1/0 is not defined. 1-x^{2} not= 0. X not= +-1.

Since x^{2} is always +, putting x=0 will give f(x)=1, else any other no. will give ans. < 1.

So, domain= R - {1,-1} Range= (-infinity,2) - {0}

ex: 1/1-0.5^2 = 1/0.75 =4/3 So, it will lie up to 2, but f(x) cant be zero !

Plz confirm this ans and also tell me if it is right...