# Find the range of f(x)=1-|x-2|

• 43
Experts when I solve by defining |x-2| I do like
case 1-x-2>or=0
1-x+2=y
x=3-y
So y belongs to R
Case 2- x-2<0
1+x-2=y
x=y+1
So y belongs to R again. Their union is again R.
But this answer is wrong. How is it wrong. Which step have I done wrong? Ans is (-infinity,1] Thanks!
• -48
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