For decolourization of one mol of KMnO4, the required litre of 30 volume H2O2 in acidified medium (1) 0 94 - Chemistry - Redox reactions

Question

For decolourization of one mol of KMnO4, the required litre of 30
volume H2O2 in acidified medium (1) 0 94 (2) 9 4 (3) 0 094 (4) 3 01

Vartika Jain · Accepted Answer

Dear Student,

In acidic medium KMnO4 is decolurised by H2O2 as follows :2 KMnO4 + 3H2SO4 + 5H2O2 → K2SO4 + 2MnSO4 + 8H2O + 5O2or, KMnO4 + 32H2SO4 + 52H2O2 → 12K2SO4 + MnSO4 + 4H2O + 52O230 volume H2O2 means 1 ml H2O2 on decompoistion gives 30 ml of O2Now, 56000 ml of O2 at STP is obtained by 52 mol of H2O2Therefore, 30 ml of O2 will be obtained from = 5256000×30=0
001 molNow, 1 mol contains 22
4 LSo, 0 001 mol will contain 22
4×0 001=0 0224

. For decolourization of one mol of KMnO4, the required litre of 30 volume H2O2 in acidified medium (1) 0.94 (2) 9.4 (3) 0.094 (4) 3.01