For the reaction, 1 g mole of CaCO3?is enclosed in 5L container? ? ?CaCO?3(s)????CaO(s) + CO?2(g)? ? ? ?K?p?= 1.16 at 1073 K then per cent dissociation of CaCO?3?is?? ? ?(1) Zero? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?(2) 6.58%? ? ?(3) 65%? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?(4) 100% Share with your friends Share 9 Vartika Jain answered this Dear Student, CaCO3(s) ↔ CaO(s) + CO2(g) C 0 0 C(1-α) Cα CαKp = Kc(RT)∆nFor the reaction, ∆n=1So, Kp = KcRTor, Kc=Kp RT =1.160.0821×1073 =0.0132For the reaction, Kc = [CaO][CO2][CaCO3]Also, since CaCO3 and CaO are solidsSo,[CaCO3]=[CaO]=1or, Kc=[CO2]or, Cα=Kcor, α=KcCHere, C=MassVolume=15So, α=0.0132×51=0.0658or, % α=0.0658×100=6.58%Hence, correct answer is (2) 22 View Full Answer