Fundamental frequency of a sonometer wire increases by SHM.If its tension is increased by 21%.How will frequency be affected if its length is increased by 10%.Please give the method. (ans=45.45Hz).
The fundamental frequency of a sonometer wire is expressed as
f = (1/ 2L). ( T/ m )1/2
here
T = tension in the string
m = mass per unit length of string
L = length of the string
now, if
tension is increased by 21%
T' = T + 0.21T = 1.21T
length is increased by 10%
L' = L + 0.1L = 1.1L
and as mass per unit length remains constant
thus, fundamental frequency becomes
f' = (1/ 2L'). ( T'/ m )1/2
= (1/ 2 x 1.1L). ( 1.21T/ m )1/2
= (1.1 / 1.1).(1/ 2L). ( T/ m )1/2
thus
f' = f
thus, the fundamental frequency does not change