# give the equation for path of projectile derive formula for time of flight derive formula for height  and range of projectile prove that hmax=4 Rmax

Let angle of projection with the horizontal axis be θ

Velocity of projection be v

Formula for range of the projectile

Let angle of projection with the horizontal axis be θ

Velocity of projection be v

Now range of the projectile is the x displacement in time of flight T

Relationship between maximum range Rmax and Hmax

• -1

Projectile motion is a two dimensional motion. It is uniformly accelerated motion.

Time of flight

Maximum height,

Horizontal range,

• 2
Hi,

When you throw an object with some initial velocity with the horizontal direction and then allow moving under the action of gravity i.e. no external force then this is known as the projectile motion.
Refer to the following projectile in which we have projected an object with initial velocity u making an angle θ with the horizontal axis.

• 4

Let angle of projection with the horizontal axis be θ

Velocity of projection be v

Formula for range of the projectile

Let angle of projection with the horizontal axis be θ

Velocity of projection be v

Now range of the projectile is the x displacement in time of flight T

Relationship between maximum range Rmax and H

• 7
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