Dear Student, a) 360o=2π radSo,1o=2π360rad = π180radb) 1o=60'So,1'=160o=160×π180rad=π10800radc) 1'=60''1''=160'=160×π10800rad=π648000rad Regards

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Dear Student,

a) . 360^{o} = 2 π r a d S o, 1^{o} = \frac{2 π}{360} r a d = \frac{π}{180} r a d b) . 1^{o} = 60' S o, 1' = {(\frac{1}{60})}^{o} = (\frac{1}{60}) \times (\frac{π}{180}) r a d = \frac{π}{10800} r a d c) . 1' = 60'' 1'' = {(\frac{1}{60})}^{'} = (\frac{1}{60}) \times \frac{π}{10800} r a d = \frac{π}{648000} r a d

Regards