If 10g of dihydrogen reacts with 10g of dioxygen to produce water. Which is the limiting reagent? ​

Dear Student,

Mass of dihydrogen = 10 g
molar mass of dihydrogen = 2 g/mol
number of moles of dihydrogen = mass/molar mass = 10/2 = 5 moles
molar mass of dioxygen = 10 g
molar mass of dioxygen = 32 g/mol
number of moles of ​dioxygen = mass/molar mass = 10/32 = 0.31 mol
The reaction between dihydrogen and dioxygen to form water is:
2H₂ + O₂ --> 2H₂O
​2 moles of dihydrogen are reacting with 1 mole of dioxygen.
Available is 5 moles of dihydrogen, so 2.5 moles of dioxygen is needed.
But dioxygen available is 0.31 mol. So, dioxygen is limiting reagent.

Regards