If 70 calorie of heat is required to raise the temp of 2 mole of an ideal gas at constant pressure from 30 to 35,calculate the degrees of freedom of the gas molecules? Share with your friends Share 15 Somnath physics answered this Here,ΔQ = 70×4.2 J n = 2 molT1=30T2=35We knowCp=1n(ΔQΔT)p=12×70×4.235−30=29.4Again,Cp−Cv=R=>Cv=Cp−R=29.4−8.3=21.1γ=CpCv=29.421.1≈1.4γ=1.4 is a value for diatomic gases that has degree of freedom =2×3−1=5 11 View Full Answer