If 70 calorie of heat is required to raise the temp of 2 mole of an ideal gas at constant pressure from 30 to 35,calculate the degrees of freedom of the gas molecules?

Here,ΔQ = 70×4.2 J n = 2 molT1=30T2=35We knowCp=1n(ΔQΔT)p=12×70×4.23530=29.4Again,CpCv=R=>Cv=CpR=29.48.3=21.1γ=CpCv=29.421.11.4γ=1.4 is a value for diatomic gases that has degree of freedom =2×31=5

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