If a constant torque of 500Nm turns a wheel of moment of inertia 100kgm2 about an axis through it's centre,find gain in angular velocity in 2s. Share with your friends Share 16 Govind answered this Given,Torque, τ=500 NmMoment of inertia, I=100 kg m2Now,τ=Iα⇒α=τI=500100=5 rad s-2Gain in angular velocity, ω=αt⇒ω=5×2=10 rad s-1 73 View Full Answer